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(C) Effective nuclear charge $(Z_{eff})$ for $N$ $(1s^2 2s^2 2p^3)$: $Z_{eff} = Z - \sigma = 7 - [2 	imes 0.85 + 4 	imes 0.35] = 7 - [1.7 + 1.4] = 7

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$a, c, d$

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(C) Effective nuclear charge $(Z_{eff})$ for $N$ $(1s^2 2s^2 2p^3)$: $Z_{eff} = Z - \sigma = 7 - [2 	imes 0.85 + 4 	imes 0.35] = 7 - [1.7 + 1.4] = 7 - 3.1 = 3.90$. This is correct.$(b)$ $Ne$ $(1s^2 2s^2 2p^6)$ and $Na^+$ $(1s^2 2s^2 2p^6)$ are isoelectronic. $Na^+$ has a higher nuclear charge $(Z=11)$ than $Ne$ $(Z=10)$, so $IP$ of $Na^+ > Ne$. Thus, statement $(b)$ is incorrect.$(c)$ Electronegativity depends on the $s$-character. $sp$ $(50\% s)$ $> sp^2$ $(33.3\% s)$ $> sp^3$ $(25\% s)$. This is correct.$(d)$ Acidic character in hydrides of group $15$ increases down the group due to the decrease in bond dissociation energy. The order is $NH_3 Therefore, statements $(a), (c),$ and $(d)$ are correct.

Column-$I$	Column-$II$
$A$. Ionisation potential	$P$. $O < F < N$
$B$. Electronegativity	$Q$. $N < O < F$
$C$. $Z_{eff}$	$R$. $O < N < F$
$D$. Electron affinity	$S$. $N < C < O$

Select the correct statements from the following:
$(a)$ Effective nuclear charge for nitrogen is $3.90$
$(b)$ $IP$ of $Ne$ is more than $Na^{+}$
$(c)$ Order of electronegativity $sp > sp^2 > sp^3$
$(d)$ Order of acidic character $NH_3 < PH_3 < AsH_3$

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$(1)$ $A$ has high electron affinity
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$(3)$ $D$ is an alkaline earth metal

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Match the following properties in Column-$I$ with their correct trends in Column-$II$:
Column-$I$ Column-$II$
$A$. Ionisation potential $P$. $O < F < N$
$B$. Electronegativity $Q$. $N < O < F$
$C$. $Z_{eff}$ $R$. $O < N < F$
$D$. Electron affinity $S$. $N < C < O$

Which of the following statements is incorrect?

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Select the correct statements from the following:$(a)$ Effective nuclear charge for nitrogen is $3.90$$(b)$ $IP$ of $Ne$ is more than $Na^{+}$$(c)$ Order of electronegativity $sp > sp^2 > sp^3$$(d)$ Order of acidic character $NH_3 < PH_3 < AsH_3$